4x-(2x+5[x-2(x-4)-5])=0

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Solution for 4x-(2x+5[x-2(x-4)-5])=0 equation:


Simplifying
4x + -1(2x + 5[x + -2(x + -4) + -5]) = 0

Reorder the terms:
4x + -1(2x + 5[x + -2(-4 + x) + -5]) = 0
4x + -1(2x + 5[x + (-4 * -2 + x * -2) + -5]) = 0
4x + -1(2x + 5[x + (8 + -2x) + -5]) = 0

Reorder the terms:
4x + -1(2x + 5[8 + -5 + x + -2x]) = 0

Combine like terms: 8 + -5 = 3
4x + -1(2x + 5[3 + x + -2x]) = 0

Combine like terms: x + -2x = -1x
4x + -1(2x + 5[3 + -1x]) = 0
4x + -1(2x + [3 * 5 + -1x * 5]) = 0
4x + -1(2x + [15 + -5x]) = 0

Reorder the terms:
4x + -1(15 + 2x + -5x) = 0

Combine like terms: 2x + -5x = -3x
4x + -1(15 + -3x) = 0
4x + (15 * -1 + -3x * -1) = 0
4x + (-15 + 3x) = 0

Reorder the terms:
-15 + 4x + 3x = 0

Combine like terms: 4x + 3x = 7x
-15 + 7x = 0

Solving
-15 + 7x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 7x = 0 + 15

Combine like terms: -15 + 15 = 0
0 + 7x = 0 + 15
7x = 0 + 15

Combine like terms: 0 + 15 = 15
7x = 15

Divide each side by '7'.
x = 2.142857143

Simplifying
x = 2.142857143

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